Neutralization reaction problem

How do I go about solving this question

Assume that vinegar is a 0.852 M solution of HC2H3O2 in water. What volume of 0.2136 M NaOH would be needed to completely neutralize 5.19 mL of vinegar?

I don't know what to do?

Number of moles of CH3-COOH = (0.852 x 5.19)/1,000 = 0.00442188 moles.

So, the volume of 0.2136 M NaOH solution are (0.00442188 x 1,000)/0.2136 = 20,701685 ml

Dear Fellow Humanoid,

Please do your own homework. You have been warned.

Regards,

Homework Police Force.