Math problem help? How many of each coin does he have

Brent has 8 more nickels than quarters. Altogether he has $6.10. How many of each coin does he have?

You can solve this using a system of equations.

Let q be the number of quarters and n be the number of nickels.

8 + q = n

25q + 5n = 610

Substitute q = n - 8 for the second equation:

25(n - 8) + 5n = 610

25n - 200 + 5n = 610

30n = 810

n = 27

So Brent has 27 nickels and 19 quarters.