How many oxygen atoms are present in 6.00 g of glucose (C6H12O6)
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How many oxygen atoms are present in 6.00 g of glucose (C6H12O6)

[From: ] [author: ] [Date: 11-12-12] [Hit: ]
022x10^23 atoms.EDIT: I made a mistake in my original answer in the second to last step, its fixed now.-Quick math is 1.......
These conversions are just killing me, I have a test on them tomorrow, if someone could explain the steps involved it would be much appreciated :) Will rate best answer, Thanks!

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First you need to find the mass percent composition of oxygen in glucose. Do this by dividing the mass of 6 oxygen atoms by the mass of a glucose molecule and multiply by 100 to get a percent.

Then, multiply 6 grams by the percent composition of oxygen to get the mass of oxygen in 6 grams of glucose. Remember that when multiplying by a percent, you need to turn it back into a regular number by dividing by 100, so 85% would be 0.85.

Next, divide the mass of oxygen in 6 grams of glucose (from the last step) by the molar mass of oxygen (16g/mol) to get the number of moles of oxygen in 6 grams of glucose.

Finally multiply the number of moles of O (from the previous step) by avogadros number, 6.022x10^23 to get the number of oxygen atoms in 6 grams of glucose.

*Avogadro's number is the number of "things" in a mole of "something" So in 1 mole of any element, there are 6.022x10^23 atoms.

EDIT: I made a mistake in my original answer in the second to last step, its fixed now.

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Quick math is 1.204 X 10^23 atoms of Oxygen :)

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