Solve the equation: 2x=-3y+10
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Solve the equation: 2x=-3y+10

[From: ] [author: ] [Date: 11-12-12] [Hit: ]
for positive integral solutions,Since t is constrained to be an integer greater than 0 or less than or equal to 1, there is only one solution (when t = 1)Note:If you want any integral solution, the just chose any integral value of t.y = 2,for 2x = 10 - 3y,......
need to show the work plz. thanks:)

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You can't solve for x and y because you have two unknowns and only one equation.

In terms of x it can be rewritten

x=-3/2y+5 divide your equation by 2

Or for y can be written as

2x=-3y+10
3y+2x=10 (adding 3y to each side)
3y=-2x+10 (taking away 2x on each side)
y=-2/3x+10/3 (dividing by 3 on wax side)

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Since there are an infinite number of real solutions, I will concentrate on showing how to find positive integral solutions.

2x = 10 - 3y
x = 5 - y - y/2

Let t = y/2

(A) so x = 5 - y - t

then if t = y/2, y = 2t

Substitute y back into the equation at (A)

x = 5 - 2t - t = 5 - 3t

so now we have

y = 2t, and x = 5 - 3t

for positive integral solutions, x and y must be > 0 so
2t > 0 then t > 0
5 - 3t > 0
-3t > -5
t < 5/3, t <= 1

Since t is constrained to be an integer greater than 0 or less than or equal to 1, there is only one solution (when t = 1) Note: If you want any integral solution, the just chose any integral value of t.


Check:

Let t = 1
y = 2, x = 2

for 2x = 10 - 3y, 4 = 10-6 = 4

Jim

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There are more variables, 2, than equations, 1, so there are infinitely many solutions.

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LOL:) ok.........

2X=-3y+10
» 2x+3y=10

»let x=0
»2(0)+3y=10
»3y=10
»y=3.33
»(0,3.33)

»let y=0
»2x+3(0)=10
»2x=10
»x=5
»(5,0)

Hope i helped :)

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Its not possible to solve...
Unless you want to solve for x or y...
I suggest you rephrase your question
1
keywords: equation,the,10,Solve,Solve the equation: 2x=-3y+10
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