A physics teacher (mass = 69.3 kg) is jogging through the woods and runs straight into a large oak tree at 5.5 m/s. Rebound speed is measured at 4.7 m/s in the opposite direction. If the time of contact with the tree is 58 milliseconds, what is the magnitude of the force that the tree exerts on the teacher?
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Force = change in momentum /time = 69.3 ( 4.7 -(-5.5))/.058 =69.3 10,2 /.058 = 12200 Ns ( to 2 sf)
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Ooooooooooooookay?????????
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K