Balanced chemical equations

How many liters of 1.2 M hydrochloric acid are needed to completely consume 0.426 mol of ZnS according to the balanced equation shown below?

ZnS (s) + 2 HCl (aq) -> ZnCl2 (aq) + H2S (l)
A. 0.36 L
B. 0.71 L
C. 0.18 L
D. 1.02 L

Molarity (M) = mole of solute / L
so...... M = mol / L

so... you want liters in this eh? then all you have to do is start the dimensional analysis with .426 mol of ZnS --> mole ratio --> end with 1.2 mole/L (which is the same as M) HCl

heres what i mean:

(.426 mol ZnS) x (2 mole HCl / 1 mole ZnS) x (1 L / 1.2 mol) = .71 L

it would really help if you write this out and analyze what I did

ZnS:HCl ratio = 1:2

Therefore, we times the moles of ZnS by 2 = 0.426x2 = 0.852

HCl = 1.2 moles per litre thus

0.852 moles / 1.2 moles per litre = 0.71L