Chemistry - Mole Concept. Help please..

Ammonia and carbon dioxide react to form water and a solid urea, (CON₂H₄). In the reaction, 48dm³ of carbon dioxide at r.t.p are converted to urea.
The equation for this reaction is 2(NH₄)+ CO₂-----> 2(H₂O) + (CON₂H₄)

Q1 .Calculate the volume of ammonia at r.t.p which reacted.

Q2. Calculate the mass of urea formed.

Thanks in advance. Please show full working! :)

Start by writing out the balanced equation properly:

2NH3(g) + CO2(g) → 2H2O(g) + CON2H4(s)

At RTP 1 mol gas has volume = 24.0dm³
48dm³ = 2 mol CO2
From the equation: 2 mol NH3 react with 1 mol CO2
Therefore 4 mol NH3 react with 2 mol CO2
At RTP , 4 mol NH3 has volume = 4*24 = 96 dm³

From the equation:
1 mol CO2 will produce 1 mol CON2H4
2mol CO2 will produce 2 mol CON2H4
Molar mass CON2H4 = 60g/mol
2mol = 120g CON2H4 produced.