How would u simplify this SIMPLE problem

i know this should be easy but im really bad at the easy stuff lol... how would i simplify

e^(-lnx)....... would the answer be simply -x? or would i have to rewrite it as e^(lnx)^-1 then that would cancel to x^-1 which would be 1/x? which method is correct?

rule: e ^ ( lnx) = x

more general: a ^ (log(x,a)) = x .... (log(x,a) = log of x with base a)

then: e^(-lnx) = 1 / (e^(lnx)) = 1/x