Standard heat of a reaction (dHrxn) problem. What am I doing wrong

Use the given information to calculate dHrxn for the production of ClF3:
(1) 2ClF + O2 --> Cl2O + OF2 dH= 167.5
(2) 2F2 + O2 --> 2OF2 dH= -43.5
(3) 2ClF3 + 2O2 --> Cl2O + 3OF2 dH= 394.1

I add equations 1 and 2, then subtract equation 3. For dHrxn, I get:

167.5 + (-43.5) + (-394.1) = -270.1 kJ

What am I doing wrong? Thank for any help.

Just divide by two: 2 F2 + 2ClF ---------> 2 ClF3 + 270.1 kJ
F2 + ClF ----------> ClF3 + 135.1 kJ, DH = - 135.1 kJ/mole