How many grams of K2SO4 are needed to prepare 500. mL of a 0.375 M solution

Can you show the steps through dimensional analysis please? I don't understand how to do this at all!
(I used the formula for molarity: mol of solute/L solution)

so molarity=mol of solute/L solution

you are given the molarity and they give you the volume in milliliters.

convert the ml to liters so you can use the molarity formula.

500ml/1000 = .5 liters.

now use the formula and you get the moles of k2so4

(.375M)=mol/(.5 liters)

(.375M) x (.5 liters) = .1875 mol k2so4

now to convert the moles to grams you multiply by the moler mass of k2so4 which you get from the periodic table.

k = 39.10 x2
s= 32.07
o= 16x4
+_______
(174.27 g/mol)

so (.1875mol) x 174.27g/mol)= 32.7 g k2so4