Chemistry 2 question HELP!
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Chemistry 2 question HELP!

[From: ] [author: ] [Date: 12-07-05] [Hit: ]
k ?A. 3.B. 2.C.......
In the first-order reaction A --> Products, the initial concentration of A is 1.56 M and the concentration is 0.869 M after 48.0 min. What is the value of the rate constant, k ?

A. 3.84 X 10-2 min-1
B. 2.92 X 10-2 min-1
C. 5.68 X 10-2 min-1
D. 1.22 X 10-2 min-1

show steps pleaseeeee!

-
ln[f] = = -kt + ln[i]
f = final
i = initial
k = constant
t = time

ln[0.869] = -k(48.0min) + ln[1.56]
-0.140412 = -k(48.0min) + 0.444686
-0.5850978 = -k(48min)
-0.5850978 / 48min = -k
-0.0121895 = -k
k = 0.0121895
k = 1.22 x 10^-2

Any more questions just let me know. I'd be glad to help!
4th of July and I'm at home bored!
Goodluck
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