How many grams of NH3 are present in 447 mL of the gas at STP
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How many grams of NH3 are present in 447 mL of the gas at STP

[From: ] [author: ] [Date: 12-07-07] [Hit: ]
Moles dont ever get squared, so you know right away that cant be correct.......
For some reason I am just not getting this. Could someone please explain. I think this is what I should do but I'm not getting the right answer.

22.4L (17.03g/0.447L) =853.4

But that is incorrect? What am I doing wrong?? :(

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(0.447 L) / (22.414 L/mol) x (17.03056 g NH3/mol) = 0.340 g NH3

You could have avoided the trouble by using the complete units for each measurement. In particular "17.03 g/mol" and "22.4 L/mol". Then you would have seen that your answer would be "853.4 g/mol^2".
Moles don't ever get squared, so you know right away that can't be correct.
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