What volume will 25.2 g of chlorine occupy at STP
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What volume will 25.2 g of chlorine occupy at STP

[From: ] [author: ] [Date: 12-07-07] [Hit: ]
2 g/70.91 g/mole=0.355 moles0.355 moles Cl2 x 22.......
This has completely baffled me. I don't just want the answer. I know the answer. I need an explanation of how to solve this. They want the answer in L. thanks!!!!

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At STP, 1 mole of a gas has a volume of 22.4 liters.
Number of liters = number of moles * 22.4

Number of moles = mass ÷ mass of 1 mole
mass of 1 mole of Cl2 = 2 * 35.5 = 71 grams
Number of moles of Cl2 = 25.2 ÷ 71
Number of liters = (25.2 ÷ 71) * 22.4

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1 mole of gas occupies 22.4 L
moles of Cl2= 25.2 g/70.91 g/mole=0.355 moles
0.355 moles Cl2 x 22.4 L/mole= 8 L
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