Chem Stock Solution Question
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Chem Stock Solution Question

[From: ] [author: ] [Date: 12-08-09] [Hit: ]
The resulting solution is 0.6 molar.......
How to prepare 500 mL of .6 M solution from a 3 M stock solution?

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C1V1 = C2V2

0.6 M x 500 mL = 3M x V2

V2 = 100 mL

Measure 100 mL of 3 M stock solution. Put it in a 500 mL beaker or flask then dilute the solution with distilled water up to the 500 mL mark of the beaker. The resulting solution is 0.6 molar.
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