Chemistry Calculation help!!
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Chemistry Calculation help!!

[From: ] [author: ] [Date: 12-10-07] [Hit: ]
thank you so much!!Where v is equal to the frequency of the wave, and h is equal to Plancks constant, which is 6.626*10^-34.......
1) How many Joules of energy are contained in a photon with a wavelength of 550nm?


2) The radio station KUSC broadcasts at 91.5 MHz. Calculate its wavelength in meters.



PLEASE PLEASE PLEASE explain what you did, thank you so much!!

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1) The energy of a photon can be found by the equation:
E(photon)=hv
Where v is equal to the frequency of the wave, and h is equal to Planck's constant, which is 6.626*10^-34.
First you have to find the frequency of the photon by c=λv. The speed of light (3.00*10^8) is equal to the frequency of the wave times the wavelength. Divide 3.00*10^8 by 5.50*10^-7 (nm to meters, which wavelength is measured in, to give you a measurement of frequency in Hertz). You get 5.45*10^14.
Now that you have the frequency, simply multiply it by Planck's constant to get the energy of the photon. You end up with 3.61*10^-19.
2) c=λv
First, convert 91.5 MHz to Hz. 10^6 is the conversion. 9.15*10^7 Hz is its frequency. Divide 3.00*10^8 (speed of light) by this number to get the wavelength. You get 3.28 meters, which is the wavelength.
Hope this helps you!

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3.626*5.45=36.1117 Add exponents when multiplying numbers in scientific notation. -34+14= -20. 36.1 must become 3.61 to follow sig figs and scientific notation, meaning you add one to the original exponent you got, b/c you made the number smaller. You end up with 3.61*10^-19. Disregard other comment

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