Find the ratio of the size of the image to that of the object
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Find the ratio of the size of the image to that of the object

[From: ] [author: ] [Date: 12-10-07] [Hit: ]
the object distance is x + f.the answer is f/x !http://www.physicsclassroom.http://www.wilmslowastro.......
The focal length of a concave lens is 'f''. An object is placed at a distance 'x' from its FIRST FOCAL POINT. The ratio of the size of the image to that of the object is?

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That 'ratio of the size of image to that of the object' is the magnification,

using Descartes formula, m = di/do = hi/ho.

So

the object distance is x + f. ( x <-----> f <-------> (mirror) ) hence it's x + f
1/f = 1/do + 1/di
1/f = 1/(x+f) + 1/di
1/di = 1/f - 1/(x+f)
1/di = [(x+f)/f(x+f)] - f/f(x+f)
1/di = [(x+f - f)/f(x+f)]
1/di = x/f(x+f)
di = f(x+f)/x

m = di/do

f(x+f)/x divided by x+f
f(x+f)/x divided by x+f is the same thing as saying multiplied by 1/(x+f)

so f(x+f)/x multiplied by 1/(x+f)

the answer is f/x !

Hope it helps :)

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Hi:

the general rule of thumbs is

d1/d2 = Os/Is

d1 = distance of Object
d2= distance of image
Os = object size
Is = Image size

the one use by mathematican ans optical people is

1/s1 + 1/s2 =1 /f

s1 = the distance from the object
s2 = the distance from the image ( or camera distance from the lens of it)
f = the Focal lenght

Here a website to explain it


http://www.physicsclassroom.com/Class/re…

http://www.wilmslowastro.com/software/fo…

http://en.wikipedia.org/wiki/Curved_mirr…

http://en.wikipedia.org/wiki/Focal_lengt…

http://search.yahoo.com/search;_ylt=A0oG…


I hope this helps
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