Calculate the molarity of an HCl solution if 31.27 mL of it reacts with 7.5955 grams of sodium carbonate (106 g/mol) according to 2 HCl + Na2CO3 → 2 NaCl + H2O + CO2. Answer in units of mol/L.
Please help, everybody! Our teacher hasn't taught a thing, and I'd greatly appreciate the help.
Please help, everybody! Our teacher hasn't taught a thing, and I'd greatly appreciate the help.
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Forget the excuses:
Find moles = Grams / Mm of Sodium Carbonate
7.5955 / 106 = 0.072mols
Ratio 1 : 2
1 Sodium Carbonate reacts to 2 HCl (see equation)
2(0.072) = 0.144mols of HCl
Now to find the molarity = Moles / Volume in L
Remember, molarity is measured in L, (1L = 1000mL)
0.144 / 31.27 / 1000 = 4.605M HCl
Find moles = Grams / Mm of Sodium Carbonate
7.5955 / 106 = 0.072mols
Ratio 1 : 2
1 Sodium Carbonate reacts to 2 HCl (see equation)
2(0.072) = 0.144mols of HCl
Now to find the molarity = Moles / Volume in L
Remember, molarity is measured in L, (1L = 1000mL)
0.144 / 31.27 / 1000 = 4.605M HCl
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Yeah, I'm sorry for my crankiness. It's late, I'm tired
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