Chemistry pre lab question help! decomposition of sodium chlorate

So i did the experiment but i was not here for the prelab question check
I have no clue for questions 3 and 4

Here is the link for it and it would explain everything
(the prelab questions are on page 1)
http://www.docstoc.com/docs/23801285/Decomposition-of-Sodium-Chlorate

PLEASE HELP ME!!!

3) Just find the sum of all the atomic masses in the formula using the periodic table:

Na = 22.99 , Cl = 35.45, O = 16.00

Molar mass (NaClO3) = 22.99 + 35.45 + 3(16.00) = 106 g/mol

Molar mass (NaClO2) = 22.99 + 35.45 + 2(16.00) = 90.4 g/mol

Molar mass (NaClO) = 22.99 + 35.45 + 16.00 = 74.4 g/mol

Molar mass (NaCl) = 22.99 + 35.45 = 58.4 g/mol

2)

Eq1: 2NaClO3(s) → 2NaClO2(s) + O2(g)

n(NaClO2) = 1.00 g ÷ 106 g/mol = 9.43x10^-3 mol = n(NaClO2) - because 1:1 mole ratio

Multiply by the molar mass of the respective product in previous question:

Mass = (9.43x10^-3 mol)(90.4 g/mol) = 0.853 g

Eq2: NaClO3(s) → NaClO(s) + O2(g)

n(NaClO2) = 1.00 g ÷ 106 g/mol = 9.43x10^-3 mol = n(NaClO)

Mass = (9.43x10^-3 mol)(74.4 g/mol) = 0.702 g

Eq3: 2NaClO3(s) → 2NaCl(s) + 3O2(g)

n(NaClO2) = 1.00 g ÷ 106 g/mol = 9.43x10^-3 mol = n(NaCl)

Mass = (9.43x10^-3 mol)(58.4 g/mol) = 0.551 g