This section I'm learning right now is called graphing transformations.
For the following functions, find y = af(k(x-p))+q.
1. f(x) = 1/x
2. f(x) = |x|
Answers:
1) y = (a/k(x - p)) + q
2) y = a|k(x - p)| + q
I don't know the following steps to take to come to the answer? In other words, even though I was given the answer I don't know how to get to the answer.
Any help would greatly be appreciated!
MB
For the following functions, find y = af(k(x-p))+q.
1. f(x) = 1/x
2. f(x) = |x|
Answers:
1) y = (a/k(x - p)) + q
2) y = a|k(x - p)| + q
I don't know the following steps to take to come to the answer? In other words, even though I was given the answer I don't know how to get to the answer.
Any help would greatly be appreciated!
MB
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If you're looking to see how to get the second equation, then it's simply a matter of thinking about how a function works. If it's f(x) = 1/x, then if you apply the function to anything else, say f(w), you're going to get 1/w.
Thus when you are looking for a* f(k(x-p)) + q, you're essentially 'replacing' x with k*(x-p), resulting in the first being 1 / [k*(x-p)] and the second being |k*(x-p)|.
Now the outer portion of those are being applied after the function is evaluated, so you multiply the end result by a and and then add q to it.
Thus giving you:
1) a* 1/[k(x - p)] + q
2) a* |k(x - p)| + q
Thus when you are looking for a* f(k(x-p)) + q, you're essentially 'replacing' x with k*(x-p), resulting in the first being 1 / [k*(x-p)] and the second being |k*(x-p)|.
Now the outer portion of those are being applied after the function is evaluated, so you multiply the end result by a and and then add q to it.
Thus giving you:
1) a* 1/[k(x - p)] + q
2) a* |k(x - p)| + q