At a tamperature of 27 degrees C and 2 atmospheric pressure, 1660 litter Oxygen gas fills a jar. Calculate the mass of Oxygen. Show calculations.
10 points for best answer.
10 points for best answer.
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Calculate the No. of moles of O2 gas using following equation
n = PV/RT = 2x1660/0.082x300 = 134.96 mol of O2 gas
So the mass of O2 = 134.96 x 32 = 4318.7 g = 4.32 kg
n = PV/RT = 2x1660/0.082x300 = 134.96 mol of O2 gas
So the mass of O2 = 134.96 x 32 = 4318.7 g = 4.32 kg
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Usually, I'd change 2 atmospheric pressure to 200KPA and the temperature 27 degrees Celsius to 300 kelvin.
Formula is PV = NRT.
(200)(1660) = N(8.314)(300)
332000 = (2494.2)(N)
332000/2494.2 =N
133.1 = N
133.1(32) = Mass.
4259.2g = Mass.
Formula is PV = NRT.
(200)(1660) = N(8.314)(300)
332000 = (2494.2)(N)
332000/2494.2 =N
133.1 = N
133.1(32) = Mass.
4259.2g = Mass.