A square circuit has a wire connecting its two sides. There is a magnetic field going out of the page that varies B = .001 * t the resistance per length of wire is .102
When the magnetic field is .9 what is the magnitude of the current through the middle section
problem shown here http://tinypic.com/r/nb9ndl/7
any help is welcome
When the magnetic field is .9 what is the magnitude of the current through the middle section
problem shown here http://tinypic.com/r/nb9ndl/7
any help is welcome
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Use Faraday's law V = N *dΦ/dt
Where Φ = B*A and N is 1
area of loop 1
A 1= (18.9875)(37.957) = 729.71 cm^2
area of loop 2
A 2= (37.957)^2 = 1440.734 cm^2
Φ1 = 0.72971*0.001t = 0.0072971t webers
Φ2 = 0.0014407t webers
d Φ1/dt = 0.0072971 webers per second
dΦ2/dt = 0.0014407 webers per second
The magnetic fields are linearly rising with time so it doesn't matter that the field is .9
V1 = 0.00072971 volts
V2 = 0.0014407 volts
the current in both loops is clockwise
R1 = 0.102*(2*0.37957 + 2*.189785)-= 0.1161 ohms
R2 = 0.102*(4*0. 37957) = 0.1549 ohm
Mid section current is V2/R2 - V1/R1= 9.301 ma - 6.285 ma= 3.016 ma the current flow from bottom to top through the middle section
Where Φ = B*A and N is 1
area of loop 1
A 1= (18.9875)(37.957) = 729.71 cm^2
area of loop 2
A 2= (37.957)^2 = 1440.734 cm^2
Φ1 = 0.72971*0.001t = 0.0072971t webers
Φ2 = 0.0014407t webers
d Φ1/dt = 0.0072971 webers per second
dΦ2/dt = 0.0014407 webers per second
The magnetic fields are linearly rising with time so it doesn't matter that the field is .9
V1 = 0.00072971 volts
V2 = 0.0014407 volts
the current in both loops is clockwise
R1 = 0.102*(2*0.37957 + 2*.189785)-= 0.1161 ohms
R2 = 0.102*(4*0. 37957) = 0.1549 ohm
Mid section current is V2/R2 - V1/R1= 9.301 ma - 6.285 ma= 3.016 ma the current flow from bottom to top through the middle section