Help with Derivatives. CALCULUS

Find the derivative of the function G(t)=t^4/(8t-1)^5
I'm not sure whether to use the quotient rule or the chain rule. I don't know how to start the problem off. Help please!

You would use both rules. You have one function divided by another: f(t) / g(u), where f(u) = u^5, and g(u) is a function of a function: g(u) = h(g(t)) where g(t) = 8t - 1

So G'(t) = (4t^3)(8t-1)^5 - (t^4)(5)(8t-1)^4(8)
................----------------------…
...............................(8t-1)^…

Now simplify:

G't = [(8t-1)^4] [(4t^3)(8t-1) - (40)(t^4)]
........------------------------------…
.......................(8t-1)^10

G'(t) = (32t^4 - 4t^3) - (40t^4)
........----------------------------
................(8t-1)^6

G'(t) = -8t^4 - 4t^3
...........--------------
...............(8t-1)^6

I hope that helps. Good luck!

You actually use both quotient and chain rules.

f ' (t) = [(8t-1)^5 *(4t^3) - t^4 *40(8t-1)^4]/(8t-1)^10

Check on the Cheggs website for help from cramster.