Hi.
See pic:
http://www.flickr.com/photos/67251822@N0…
This just isn´t explained so I need help.
Please explain a little.
Thanks
See pic:
http://www.flickr.com/photos/67251822@N0…
This just isn´t explained so I need help.
Please explain a little.
Thanks
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The answer is 1. The 555 timer can be used as a rectangular waveform oscillator or a monostable multivibrator.
To use it as a rectangular waveform oscillator, you use two resistors and a capacitor. PIns 4 and 8 of the 555 timer are tied to Vcc and pin 1 is grounded. One side of the first resistor (R1) connected to Vcc, the other side to pin 7 of the 555. One side of the second resistor (R2) also connects to pin 7 of the 555, its second side connects to the capacitor and pins 2 and 6 of the 555. The other side of the capacitor is grounded. Basically the capacitor charges from 1/3 Vcc to 2/3 Vcc, and then discharges to 1/3 Vcc. When the capacitor is charging the 555's output on pin 3 is high. And when the capacitor is discharging the 555's output is low. The high period is 0.693(R1 +R2)(C) and the low period is 0.693(R2)(C).
To use it a monostable multivibrator, you use one resistor and capacitor.One side of the resistor is connected to Vcc, the other to the capacitor and pin 7 of the 555. The other side of the capacitor is grounded. A low going pulse on pin 2 causes the 555 to output a high pulse on pin 3 for a time of 1.1(R)(C). Again pins 4 and 8 of the 555 is connected to Vcc and pin 1 is grounded.
To use it as a rectangular waveform oscillator, you use two resistors and a capacitor. PIns 4 and 8 of the 555 timer are tied to Vcc and pin 1 is grounded. One side of the first resistor (R1) connected to Vcc, the other side to pin 7 of the 555. One side of the second resistor (R2) also connects to pin 7 of the 555, its second side connects to the capacitor and pins 2 and 6 of the 555. The other side of the capacitor is grounded. Basically the capacitor charges from 1/3 Vcc to 2/3 Vcc, and then discharges to 1/3 Vcc. When the capacitor is charging the 555's output on pin 3 is high. And when the capacitor is discharging the 555's output is low. The high period is 0.693(R1 +R2)(C) and the low period is 0.693(R2)(C).
To use it a monostable multivibrator, you use one resistor and capacitor.One side of the resistor is connected to Vcc, the other to the capacitor and pin 7 of the 555. The other side of the capacitor is grounded. A low going pulse on pin 2 causes the 555 to output a high pulse on pin 3 for a time of 1.1(R)(C). Again pins 4 and 8 of the 555 is connected to Vcc and pin 1 is grounded.
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Click google search and type " 555 timer ".
Then select link one by one and read them........
http://www.google.ca/search?q=555+timer&…
Then select link one by one and read them........
http://www.google.ca/search?q=555+timer&…
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Umm, the text in the link is all text. There is just a list of the functions a 555 can perform. What is to be explained?