Determine the angular momentum of a 77-g particle about the origin of coordinates when the particle is at

Determine the angular momentum of a 77-g particle about the origin of coordinates when the particle is at

x = 4.1m , y = -6.0m and it has a velocity
v = (3.3i - 8.4k) m/s

find the x,y and z components of the angular momentum

To find angular momentum, we need to take the cross product of the position vector with the linear momentum:

r = <4.1 , -6.0 , 0>

p = (0.077)*<3.3 , 0 , -8.4)

The cross product (angular momentum) is:

(0.077)*<-6.0*-8.4 - 0 , -4.1*-8.4 + 0 , 0 + 6.0*3.3>

= <3.88 , 2.65 , 1.52>
*These are the components.

The magnitude is: Sqrt[ 3.88^2 + 2.65^2 + 1.52^2 ] = 4.94 kg m^2/s