How do i calculate voltage drops in series circuit

Can someone teach me how to calculate voltage drops in series circuit?

There are two methods:

Calculate the series current by dividing the applied voltage by the total resistance. Calculate each resistor's voltage drop by multiplying its resistance times the series current.

Calculate the proportion of the total for each resistor by dividing its resistance value by the total resistance. Multiply each resistor's proportion times the applied voltage to find its voltage drop.

E_total = I_total * R_total

Edit:
Components in a series circuit share the same current:
I_total = I_1 = I_2 = . . . I_n

Total resistance in a series circuit is equal to the sum of the individual resistances:
R_total = R_1 + R_2 + . . . R_n

Total voltage in a series circuit is equal to the sum of the individual voltage drops:
E_total = E_1 + E_2 + . . . E_n

Regards.