Help!! :(
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All logs are to base 2 so leave that out.
log(x) + 2*log(3) = log(x + 5)
log(x) + log(9) = log(x + 5) ....... using rule a*log(b) = log(b^a)
log(9x) = log(x + 5) ............ using rule log(a) + log(b) = log(a*b)
9x = x + 5 ----> 8x = 5 ----> x = 5/8
log(x) + 2*log(3) = log(x + 5)
log(x) + log(9) = log(x + 5) ....... using rule a*log(b) = log(b^a)
log(9x) = log(x + 5) ............ using rule log(a) + log(b) = log(a*b)
9x = x + 5 ----> 8x = 5 ----> x = 5/8