Scientists want to place a 3800 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:
mmars = 6.4191e23 kg
rmars = 3.39736 m
G = 6.67428e-11 N-m2/kg2
1. What is the force of attraction between mars and the satellite?
-- the equation I'm using is F=G(m1m2/r^2) so..
6.67428e-11((6.4191e23 x 3800)/(3.397e6^2)
My homework is online and I am not coming up with the right answer for some reason. What am I doing wrong?
Please help!!
mmars = 6.4191e23 kg
rmars = 3.39736 m
G = 6.67428e-11 N-m2/kg2
1. What is the force of attraction between mars and the satellite?
-- the equation I'm using is F=G(m1m2/r^2) so..
6.67428e-11((6.4191e23 x 3800)/(3.397e6^2)
My homework is online and I am not coming up with the right answer for some reason. What am I doing wrong?
Please help!!
-
you are using the correct equation, but the incorrect value for r
the problem states that the satellite will be 2 times the radius of mars above the surface; this means that the distance of the satellite from the center of mars is 3 times mars' radius; so the denominator should be (1.019x10^7)^2
the problem states that the satellite will be 2 times the radius of mars above the surface; this means that the distance of the satellite from the center of mars is 3 times mars' radius; so the denominator should be (1.019x10^7)^2