What is the magnitude of acceleration using pulley

A mass m1 = 6.9 kg rests on a frictionless table. It is connected by a massless and frictionless pulley to a second mass m2 = 3.7 kg that hangs freely.

a) what is the magnitude of acceleration on block 1(on top of the table)?
--I've seriously tried everything. I've been working on this forever! I know that F=ma. The only force acting in the horizontal direction on block a is Tension.

b)What is the tension in the string?

Please help! I am getting so frustrated with this class to the point of wanting to drop it. I need it for my major though so it would be a huge waste of money.

Very simple,
net force on the system
= 3.7 g
system mass = 6.9 + 3.7 = 10.6kg
magnitude of acceleration of the system mass
= 3.7 * 9.81 / 10.6
= 3.42 m/s^2
answer
magnitude of acceleration on block 1.

b) the tension in the string
= force on mass m1
= 6.9 * 3.42
= 23.6N
answer

Let the tension in the string is T Newton and the acceleration of the system is a m/s^2
(a)=>By m2g - T = m2a ----------(i)
=>T = m1a -------------------(ii)
=>by (i) + (ii) :-
=>m2g = (m1+m2)a
=>a = m2g/(m1+m2)
=>a = (3.7 x 9.8)/(6.9+3.7)
=>a = 3.42 m/s^2
(b) by putting the value of a in (ii):-
=>T = 6.9 x 3.42 = 23.60 Newton

a) Force acting on the resting mass of the table = F1 = T = m2 g and by the Newton's 2nd law of
motion F1 = T = m1 a = m2 g ==> a = (m2 / m1) g = (3.7/6.9)*(9.8) m/s^2 = 5.25 m/s^2
b) Tension in the string = T = m2 g = 3.7*9.8 = 36.3 N