In Figure 3, if m Arc PM = 40 and m Arc JKM = 210, then m Arc JP =______°
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In Figure 3, if m Arc PM = 40 and m Arc JKM = 210, then m Arc JP =______°

[From: ] [author: ] [Date: 11-05-16] [Hit: ]
so JP, the missing arc in the top half is 180 - 30 - 40 = 110.......
In Figure 3, if m Arc PM = 40 and m Arc JKM = 210, then m Arc JP =______°

http://www.learningbygrace.org/geom/imag…

IS IT 80???

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ok. well right off the bat, we know that arc JK = 180 degrees, since it is half of the circle

by the same logic the top half also equals 180 degrees.

we know that PM = 40, and JKM = 210

but we already know that JK = 180 , so MK = 30.

so JP, the missing arc in the top half is 180 - 30 - 40 = 110.
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