Solve the following equations: sin(x - (π/6)) = 1/2 , 0 <= x <= 2π

a) sin(x - (π/6)) = 1/2 , 0 <= x <= 2π

b) cos(2x) = -1/2 , 0 <= x <= 2π

c) 2sin(3x) - √3 = 0 , 0 <= x <= 2π

only one question at a time.

a)

sin(x - (π/6)) = 1/2

since sin A = 1/2, then A = π/6, 5π/6

==> x - π/6 = π/6 and 5π/6

x = π/3 and π