4y1/3 + 5y8/2 = 12y+6/6
I believe 『y = 62/11』 but according to my text book 『y = 32/11』
I believe 『y = 62/11』 but according to my text book 『y = 32/11』

(4y  1) / 3 + (5y  8) / 2 = (12y + 6) / 6
6[(4y  1) / 3] + 6[(5y  8) / 2] = 6[(12y + 6) / 6]
2(4y  1) + 3(5y  8) = 12y + 6
8y  2 + 15y  24 = 12y + 6
8y + 15y  12y = 6 + 2 + 24
11y = 32
y = 32/11
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6[(4y  1) / 3] + 6[(5y  8) / 2] = 6[(12y + 6) / 6]
2(4y  1) + 3(5y  8) = 12y + 6
8y  2 + 15y  24 = 12y + 6
8y + 15y  12y = 6 + 2 + 24
11y = 32
y = 32/11
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(4y  1)/3 + (5y  8)/2 = 2y + 1
8y  2 + 15y  24 = 12y + 6
11y = 32
y = 32/11
8y  2 + 15y  24 = 12y + 6
11y = 32
y = 32/11