Cesium137 undergoes beta decay and has a half life of 30 years. How many beta particles are emitted by a 14.0 gram sample of cesium137 in three minutes?

14g of Cesium137 contains 14/137 moles of Cesium = 14/137 * 6.02 * 10^23 atoms = 6.15 * 10^22 atoms
In decay,
N(t) = N0 (1/2)^(t/halflife)
where N(t) is what is left, undecayed
N0 is starting quantity
t is time
The fraction that decays is then
1  (1/2)^(3/(30*365.25*1440)) as there are 365.25*1440 minutes in a year
=1.32*10^7
and the amount of particles that decay is
6.15 * 10^22 * 1.32 * 10^7
=8.1 * 10 ^15
In decay,
N(t) = N0 (1/2)^(t/halflife)
where N(t) is what is left, undecayed
N0 is starting quantity
t is time
The fraction that decays is then
1  (1/2)^(3/(30*365.25*1440)) as there are 365.25*1440 minutes in a year
=1.32*10^7
and the amount of particles that decay is
6.15 * 10^22 * 1.32 * 10^7
=8.1 * 10 ^15