How do I figure it out?
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4cos^4(x) = 4{1 - sin^2 (x)}^2
= 4{1 - 2sin^2 (x) + sin^4 (x)}
sin(x) is an infinite series [x - x^3/3! + x^5/5! - ..........]
The only integer without variable x is 4 .
= 4{1 - 2sin^2 (x) + sin^4 (x)}
sin(x) is an infinite series [x - x^3/3! + x^5/5! - ..........]
The only integer without variable x is 4 .
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4cos^5(x)/5sin(x) you raise the power by one and divide the whole function by the new power and the differential of cos x , now in return can i have something ;)
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Suitable values of cos x = ±1, ±1/√2
=> 4cos^4(x) = 4(1) or 4(1/4) = 4 or 1.
Note that 4th power is always +ve.
=> 4cos^4(x) = 4(1) or 4(1/4) = 4 or 1.
Note that 4th power is always +ve.
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It can be an integer if cosx is an integer i.e. -1, 0 and 1 so the integer value of 4cos^4(x) can be from 0 to 4.