ALGEBRA 1!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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ALGEBRA 1!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[From: ] [author: ] [Date: 11-05-24] [Hit: ]
Simply cross multiply if Im not mistaken.You should be left with 147y^22/10x^45.As for the last two questions, you are on your own for those.......
These all need to be simplified. Please show me the work on how to get the answer. & the answer.

1. (x+7(x-4) over (x-7)(x-4)

2. 2x^5 over 7y^2 times 21y^11 over 5x^9

3. 2x^2-18 over 4x^8 divided by 6x^2+6x-36 over 8x^4

4. 3(x-7) over (x+2)(2x-1) times 4x^2+6x-4 over 4x-28

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Is the first one supposed to have a bracket: (x+7)?

Anyways #1. (x+7)(x-4) over (x-7)(x-4), cross out the (x-4) on both sides of the fraction. Answer = x+7 over x - 7.

*looks at the rest of questions* Um... nevermind, you're on your own.

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When given (x+7)(x-4)/(x-7)(x-4) you simply cross out the (x-4) on both top and bottom and are left with (x+7)/(x-7).

when dealing with 2x^5/7y^2 * 21y^11/5x^9, Simply cross multiply if I'm not mistaken. You should be left with 147y^22/10x^45.

As for the last two questions, you are on your own for those.
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