Maths problems and questions
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Maths problems and questions

[From: ] [author: ] [Date: 11-05-26] [Hit: ]
Find the time in minutes it takes for light to travel from the sun to Earth? The speed of light is 3.0 x 108 m/s. Speed=distance/time 2) An aluminium rod has length of 6cm and a cross-sectional area of 1.5cm2. Find the volume in m3.......
I haven't had to solves any maths questions for many years now so I am very rust and would like some help with these questions. The answers must include workings out.

1) Earth is approximately 1.5 x 108 km from the sun. Find the time in minutes it takes for light to travel from the sun to Earth? The speed of light is 3.0 x 108 m/s. Speed=distance/time


2) An aluminium rod has length of 6cm and a cross-sectional area of 1.5cm2. Find the volume in m3.The density of aluminium is 2700kg/m3. Given that density= mass/volume
Calculate the mass of the rod. Convert your answer to scientific notation.


3) A 0.500m length of wire with a radius of 0.001m is found to have a resistance of 2.53 x 10-3 ohms. Calculate Resistivity p using the formula R=("p" ×l)/A where R is the resistance, A is the cross-sectional area and l is the length of the wire


4) Calculate the Body Mass Index, BMI, for a person of ‘weight’ 12 stone 5 pounds and height 5 feet 10 inches. Body Mass Index, in units of kg m-2, is given by:
(1 stone = 14 pounds, 1 kg = 2.20 pounds, 1 foot = 12 inches and 1 inch = 2.54 cm)


5) Ammonia, NH3, is formed by the combination of nitrogen and hydrogen in the ratio by mass of 6.0: 1.3. Calculate (to 2 sf) the mass of hydrogen that will react with 4.3 g of nitrogen.


6) Find the volume of a container necessary to hold .8kg of mercury. The density of mercury is 13.55 g/cm3. Mercury is kept in a cylindrical container with radius 2cm. Find the minimum height in cm of the container required to keep the liquid.

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1. Speed = dist/time
therefore, time = distance/speed.
from this we can calculate the time in seconds. but first u need to convert KM to M for the distance given.
i.e. : (1.5 * 10^8) Km = (1.5 * 10^8 * 10^3) m = (1.5 * 10^11) m
this implies that; time = (150000000000)/(300000000) = 500 seconds
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