Solve using Quadratic Formula help

1.) x^2 - 60 = -11

2.) 12x^2 + 3x = 0

(Show work please)

1. Add 11 to both sides: x^2 - 49 = 0. The quadratic formula says that x = [-b (plus or minus) the square root of (b^2 - 4ac)]/2a, where a is the coefficient on the quadratic term, b is the coefficient on the linear term and c is the constant. In this case, a=1, b=0 and c=49. x = 0 plus or minus the square root of (0 - 4 * 1 * -49)/2, which is (the square root of 196)/2, which is 14/2, or 7.

2. a=12, b=3, c=0; x = [-3 plus or minus sqrt(9 - (4*12*0))]/24, which is [-3 plus or minus sqrt(9)]/24, which simplifies to 0 or -9/24.

what's hard about it? the only hard part is remembering the formula! it's x=[-b±√(b²-4ac)]/2a for a quadratic equation 0=ax²+bx+c. there are usually two different answers, one in which you treat the "±" symbol as a plus sign and another in which you treat it as a minus sign.

For number 1, you have to rearrange it to look like 0=ax²+bx+c, so add 11 to both sides and you get x²-49=0. since there is no x term, b is 0 (zero). a is 1 and c is -49.

Number 2 is pretty much straight forward. Since there is no constant term, c is 0. a is 12 and b is 3.

Just plug everything in to a calculator. It's really simple.

Add 11 to both sides to get x^2 - 49
Then simplify to (x - 7) (x + 7)

The GCF is 3x, so you divide by 3x to get 3x (4x+1)