options are
a) (2,-3), b) (-1,-1), c) (-2,-1), d) (-1,1), (-1,-5)
Can you please show workings
a) (2,-3), b) (-1,-1), c) (-2,-1), d) (-1,1), (-1,-5)
Can you please show workings
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Inspecting y = 2x - 3 one sees that if x = 0 then y = -3
that gives one point already
I do not see a minus 3 anywhere except in choice (a) BUT the x value is wrong there, so we'll have to do some more work...
This equation is of the form y = mx + b where m is the slope which is the the rise or fall of y per unit x
The slope is 2 and that means y goes UP by 2 for every 1 unit increase in x
Also we can set y = 0 and see that x = 1.5 giving another point
We got 2 points so far, giving YOU the grapher a way to DRAW this line on graph paper
YOU draw the line from -3 on the Y-axis to 1.5 on the X-axis...
Now extend that line.
YOU the grapher should then see that only ONE choice is correct and that the four lettered choices are wrong.
that gives one point already
I do not see a minus 3 anywhere except in choice (a) BUT the x value is wrong there, so we'll have to do some more work...
This equation is of the form y = mx + b where m is the slope which is the the rise or fall of y per unit x
The slope is 2 and that means y goes UP by 2 for every 1 unit increase in x
Also we can set y = 0 and see that x = 1.5 giving another point
We got 2 points so far, giving YOU the grapher a way to DRAW this line on graph paper
YOU draw the line from -3 on the Y-axis to 1.5 on the X-axis...
Now extend that line.
YOU the grapher should then see that only ONE choice is correct and that the four lettered choices are wrong.
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substitute each given choices to the equation
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get a graphing calculator or google, winplot