Finding the molarity of an NaOH solution

If 120ml of a 0.1 M acid is neutralized by 98ml of NaOH, what's the molarity of the NaOH solution?
Please show work. Thank you. You guys rock!

Number of moles of H+ ions from the acid = 0.1 / 1000 x 120 = 0.012 moles
To neutralize, number of moles of H+ = number of moles of OH-
Therefore number of moles of OH- = 0.012
Since 98ml of NaOH was used, molarity of NaOH = 0.012 / 98 x 1000 = 0.122448979M