Find the area of a triangle with side lengths 11, 16, and 17 inches

area=√[s(s-a)(s-b)9s-c)] s=(1/2)(a+b+c) a=11 b=16 c=17
s=22
area=√[22(22-11)(22-16)(22-17)]
=√[22(11)(6)(5)]
=85.206 in²

Is this a right triangle or what? More info would help.