How do I write the proper Algebraic Equation for this word problem

What 3 consecutive integers equal 9?

Now I know the answer is 2+3+4 but, how would I write it?

I would right it like this:

Let X equal the second integer
3X = 9

3X ÷ 3 = 9 ÷ 3
X = 3


Therefore the first integer is 3 - 1 = 2 and the second integer is 3 + 1 = 4

Is this the correct way of writing it? I don't wanna get marks off for writing it incorrectly. If it is incorrect how can I change it to write it correctly?

Thanks :)

Let x be the first of the consecutive integers. The statement says :
--------------------------------------…

[ x ] + [ x + 1 ] + [ x + 2 ] = 9

3x + 3 = 9

x = 2 <-----------------------------------

x + 1 = 3 <-----------------------------

x + 2 = 4 <-------------------------------------

The consecutive integers are [ 2 , 3 , and 4 ] <----------------------

I turned the word statement into an equation. This takes practice , but is most
worthwhile.

You would have to show the representation of the 3 numbers..

as...

We consider the 2nd number to be X

Thus, 1st number : X - 1
3rd number : X + 1

Thus, according to the given condition,
( X -1 ) + X + ( X + 1 ) = 9
3 X = 9

And then continue with the solution you have written....

x+1 + x + x-1 = 9
3x = 9
x = 3
x-1 = 2
x+1 = 4

2, 3, 4


only difference is that that is showing x is the middle integer. you could also to x + x+1 + x+2 = 9 where x is the first integer.

x + (x+1) + (x+2) = 9
solving for "x" which is the first integer