What is the equation of the parabola that opens up, has a vertex of (-5,0), and a y-intercept of 50

please help.

Standard equation of parabola
y = Ax^2 + Bx + C
when x = 0, y =50
50 = C
x co-ordinate of vertex = -B/2A = -5
B = 10A
y = Ax^2 + 10A*x+50
when x=-5 y=0
0=25A-50A+50
A = 2
y = 2x^2+20x+50
y = 2(x^2+10x+25)
y = 2(x+5)^2

y = 2 ( x + 5)^2