Algebra 2 help? Please

There are two numbers with the following properties. 1) The second number is 3 more than the first number. 2) The product of the two numbers is 9 more than their sum. Which of the following repressents possible values of these two numbers.

A. -6, -3,
B. -4,-1
C. -1, 4
D. -3, 6

one number is x, the other is x+3
the product is x(x+3)
the sum is 2x + 3
apply 2)
x(x+3) = 2x + 3 + 9
x^2 + 3x - 2x - 12 = 0
x^2 + x - 12 = 0
(x+4)(x-3) = 0
x = -4 or x = 3
not sure how this fits ABCD you asked for

From statement (1), we have y = 3 + x

From statement (2), we have xy = 9 + x + y

Substituting for y in statement (2), we have

x(3+x) = 9 + x + 3 + x

3x + x^2 = 2x + 12

x^2 + 3x - 2x - 12 = 0

x^2 + x - 12 = 0

(x+4)(x-3) = 0

x = -4 or x = 3

B is the only choice that uses one of these as the smaller number.

Jen

If x is the first x+3 is the second. Their product is x(x+3) so x(x+3) = x+(x+3)+9.
which becomes x^2 + x - 12 =0 or (x+4)(x-3)=0 means x= -4 or 3
But no alternative matches with this answer. Funny!

First number be x
Second number = x+3

x ( x+3) = x + ( x+ 3) + 9

x^2 + 3x = 2x + 12

x^2 + x -12 = 0

( x + 4) ( x-3) = 0

x = -4 Or 3