Y=1/sqrt 2π^e−x2/5 y = 0 x = 0 x = 1
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Y=1/sqrt 2π^e−x2/5 y = 0 x = 0 x = 1

[From: ] [author: ] [Date: 11-06-19] [Hit: ]
y = [ 1/√(2π) ] * e^(−x^2/5)-can u post the question again so i can answer it for you?Report Abuse -i got this question but can you answer this question for me please.http://answers.yahoo.com/question/index;_ylt=Auwlcm73.n96qA4imZjGj03ty6IX;_ylv=3?......
Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis. (Round your answer to three decimal places.)

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do u mean this function:

y = [ 1/√(2π) ] * e^(−x^2/5)

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can u post the question again so i can answer it for you?

Report Abuse


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i got this question but can you answer this question for me please.

http://answers.yahoo.com/question/index;_ylt=Auwlcm73.n96qA4imZjGj03ty6IX;_ylv=3?qid=20110619052326AAFZlu7

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