Help please algebra equation

The equation of a line in point-slope form is y-4=-4(x-1). Write the equation in standard form.
Please help by explaining how you got that answer

I first solve the equation for y and then write it in Standard form
y-4=-4(x-1)
y-4=-4x+4
y=-4x+8 this is the y-intercept form
4x+y=8 this is the standard form

Well, as the other answerers put, I think that y=-4x+8 is in slope intercept form.
For standard form, I think you mean ax + by = c, which would be 4x + y = 8.
To do this, you just multiply out -4(x-1) to get y - 4 = -4x +4. Then, move the -4x to the other side and -4 to the other side... So you get 4x + y = 8.
A = 4 B = 1 C = 8

I hope this is what you were asking for!

When I took algebra, I'm sure the correct equation was y=mx+b.
So, I'm not one hundred percent sure, but wouldn't you subract the 4 next to the y and get it over by the x?

y-4=-4(x-1)
y = -4x + 8, which is the standard form of y=mx+c
m= -4 and c=8

y-4=-4x+4
y=-4x+8

standard for is y=mx+b

Hope that helps!

that just means to get the y by itself. Multiply out the right side first, then add 4 to both sides to get y alone
y-4=-4(x-1)
y-4=-4x+4
y=-4x+8