Solve theis math problem

the graph of a quadratic function that has -2 as a root? plz put pic of solution

The root of a function is where it crosses the x axis, ie. the x intercepts. If the only root is -2, just write it as a factor. That is if the root is -2, a factor of the equation MUST BE (x+2). Since -2 is the only root, that is the only factor so just square it. (x+2)^2.

Drawing:
http://graphsketch.com/render.php?eqn1_c…

if a quadratic has -2 as a root, that means the graph crosses the x-axis at (-2, 0)

aka, that x = - 2 (because the x-coordinate is -2).

rearrange to

x + 2 = 0

THEREFORE in factored form, (x+2) is a root.

If we assume that it is the ONLY root....

0 = (x+2)(x+2)

0 = (x+2)^2

is how we found that root (because when the graph crosses the x-intercept, y =0 )

y = a(x+2)^2 <-----factored form: y= a(x+?)(x-?)

since we don't know the value of a, and it hasn't given us a point we can sub in to find that value, we'll just leave it as 1:

y= 1(x+2)^2

y = (x+2)(x+2)

or expand for standard form

y= x(x) + x(2) + 2(x) + 2(2)

y= x^2 +2x +2x +4

y= x^2 +4x +4

do it urself noob