Given: f(x) = Ix-3I + IxI - 6 Find all roots to the nearest 0.001 PLEASE HELP!!

5. Given: f(x) = Ix-3I + IxI - 6
Find all roots to the nearest 0.001
Will give 10 pts for best answer!

Both absolutes Plus
(x - 3) + x - 6 = 0
2x - 9 = 0
2x = 9
x = 4.5
solution (4.5 , 0)

x absolute is minus
(x - 3) - x - 6 = 0 No solution.

x absolute plus; (x - 3) minus
-(x - 3) + x - 6 = 0
No solution. The x's cancel out

Both are minus.
-(x - 3) - x - 6 = 0
-2x + 3 - 6 = 0
-2x - 3 = 0
-2x = 3
x = -3/2

Solution (-3/2 , 0)