Solve for x, simple algebra 1

3x-r=r(-3+x)
Show line by line and explain steps please! Thanks

3x -r = r ( x -3)

3x -r = rx - 3r

3x - rx = -3r +r = -2r

x ( 3 - r) = -2r

x = -2r / ( 3- r) ANSWER

3x - r = r(-3 + x) Original problem.
3x - r = -3r + rx Distributive property.
3x = -2r + rx Add r to both sides of the equals sign.
x = -2r + rx/3 Divide both sides by 3. (the / means that the 3 is under the rest of it)

So basically: x = -2r+rx
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3

3x − r = r(−3 + x)
3x − r = −3r + rx
3x − rx = −3r + r
x(3 − r) = −2r
x(r − 3) = 2r
x = 2r / (r − 3).

Add r to each side:
3x=-2r -rx
Add rx to each side:
x(3+r)= -2r
Divide by (3+r)
x = -2r/(3+r)