Given that x=2 is one root of the equation x² + x + m = 0, find the other root and the value of m.

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Given that x=2 is one root of the equation x² + x + m = 0, find the other root and the value of m.

[From: ] [author: ] [Date: 11-09-08] [Hit: ]

So the other root is -3.So if one root is 2,......

using sum/product of roots method.

thanks

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substitute x=2 , 4+2+m=0 => m = -6

equation is now, x^2 +x -6 =0 => (x-2)(x+3) = 0
roots are, 2, -3

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plug in 2 for x in the equation: 2² + 2 + m=0
4+2+m=0
6+m=0
m=-6

so the equation is x² + x - 6 = 0
Factor:
(x+3)(x-2)=0
x=-3 or x=2
So the other root is -3.

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Sum of roots is -1 (-b/a)
So if one root is 2, the other root must be -3

M is the product of the roots = -6

1

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