Algebra question help!

(x)(-x^2+6x-5)

i'm assuming you meant that this = 0?
(x)(-x^2 + 6x - 5) = 0
either x = 0 or -x^2 + 6x - 5 = 0
-x^2 + 6x - 5 = 0
x^2 - 6x + 5 = 0
(x - 5)(x - 1) = 0
x = 1, 5
therefore the solution set is 0, 1, and 5.

x² - 3x = - 5 + (- 3)²
x² - 3x = - 5 + 9
(x - 3)² = 4
x - 3 = ± 2

x = 2 + 3, x = 5
x = - 2 + 3, x = 1

Answer: x = 0, 5, 1

distribute

the answer

-x^3+6x^2-5x

to get that just multiply x by the number in pranthisis

distribute x:
(-x^3+6x^2-5x)

-x^3+6x^2-5x