Can you help with Algebra 2

Write an equation of the line that passes through the given points.

(-1, 3) (2,9)

Write an equation of the line that passes through the given point and has the given slope.

(-4, 2), m= 3/2

Thanks for answering.

Using y= mx +b equation first solve for slope = m

slope= m = rise over run = difference in vertical coord(y) over difference in horizontal coord(x)

so from the 2nd to the first point we have m=(9-3)/(2- -1) = 6/3 = 2

So y = 2x +b is where we are at, use either pt, (2,9) is all positives so maybe i would choose that

9 = 2(2) + b so b = 5

So y =2x + 5 is the equation of that line

For the 2nd questions just plug those 3 numbers into the equation y=mx+b and solve for b

2= (3/2)(-4) + b

2 = -6 + b

8 = b therefore y = (3/2)x + 8

Write an equation of the line that passes through the given points.
(-1, 3) (2,9)

(y-3)/(x+1) = (9-3)/(2+1)
y-3 = 2x + 2

2x - y = -5

Write an equation of the line that passes through the given point and has the given slope.
(-4, 2), m= 3/2

(y-2)/(x+4) = 3/2
y-2 = (3x+12)/2

3x - 2y = -16

(-1,3) → (2,9)
rise = 6
run = 3 ∙ ∙ ∙ ∙ ∙ slope - 6/3 = 2

so y – 3 = 2(x + 1)


y – 2 = (3/2)(x + 4)

Qu 1
m = 6 / 3 = 2
y - 9 = 2 ( x - 2 )
y = 2x + 5

Qu 2
y - 2 = (3/2) ( x + 4 )
y = (3/2) x + 8